Question

Find out the following squares by using the identities:
${(x-\frac{1}{x})}^2$

Answer 1

We know identity $(a-b{)}^2=a^2+b^2-2ab$

Using this identity, we get

${(x-\frac{1}{x})}^2=x^2+\frac{1}{x^2}-2\times \frac{1}{x}\times x$

$=x^2+\frac{1}{x^2}-2$