Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of $4 m$ rotating at $120$ revolutions per minute.

4 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 m / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $25 m / s$
Given : $ν = 120$ $r p m = \frac{120}{60} = 2$ $r p s$

Radius of the plate $r = \frac{D}{2} = \frac{4}{2} = 2$ m
Instantaneous velocity $v = r w = r (2 π ν) = 2 \times 2 π \times 2 \approx 25$ $m / s$

Suggest Corrections

Similar questions

Q. The instantaneous velocity of a point on the outer edge of a disk with a diameter of 4 m that is rotating at 120 revolutions per minute is most nearly:

A ball of mass 4 kg moving with a velocity of 12 m/s impinges directly on another ball of mass 8 kg moving with velocity of 4 m/s in the same direction. Find their velocities after impact (if $e$ = 0.5)

Q. A ball of mass

10 kg

is moving with a velocity of

10 m/s

. It strikes another ball of mass

4 kg

, which is moving in the same direction with a velocity of

4 m/s

. If the collision is elastic their velocities after collision will be respectively

Q. If velocity of a particle is

v (t) = 2 t - 4 m/s

, the average speed and magnitude of average velocity of the particle in

10 sec

respectively are

Q. Two blocks of masses

4 kg

and

2 kg

are placed on a frictionless surface and connected by a spring. An external kick gives a velocity of

12 m/s

to the heavier block in the direction towards the lighter one. The magnitude of the velocities of two blocks in the center of mass frame, after the kick, are respectively

Join BYJU'S Learning Program

Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of 4m rotating at 120 revolutions per minute.

The correct option is D 25m/sGiven : ν=120 rpm=12060=2 rpsRadius of the plate r=D2=42=2 mInstantaneous velocity v=rw=r(2πν)=2×2π×2≈25 m/s

Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of $4 m$ rotating at $120$ revolutions per minute.

The correct option is D $25 m / s$
Given : $ν = 120$ $r p m = \frac{120}{60} = 2$ $r p s$

Radius of the plate $r = \frac{D}{2} = \frac{4}{2} = 2$ m
Instantaneous velocity $v = r w = r (2 π ν) = 2 \times 2 π \times 2 \approx 25$ $m / s$