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Standard XII

Physics

Relation between Linear and Angular Speed

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Question

Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of $4 m$ rotating at $120$ revolutions per minute.

4 m / s

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6 m / s

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12 m / s

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25 m / s

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50 m / s

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Solution

The correct option is D $25 m / s$
Given : $ν = 120$ $r p m = \frac{120}{60} = 2$ $r p s$

Radius of the plate $r = \frac{D}{2} = \frac{4}{2} = 2$ m
Instantaneous velocity $v = r w = r (2 π ν) = 2 \times 2 π \times 2 \approx 25$ $m / s$

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Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of 4m rotating at 120 revolutions per minute.

The correct option is D 25m/sGiven : ν=120 rpm=12060=2 rpsRadius of the plate r=D2=42=2 mInstantaneous velocity v=rw=r(2πν)=2×2π×2≈25 m/s

Find out the instantaneous velocity of a point on the outer edge of a circular plate with a diameter of $4 m$ rotating at $120$ revolutions per minute.

The correct option is D $25 m / s$
Given : $ν = 120$ $r p m = \frac{120}{60} = 2$ $r p s$

Radius of the plate $r = \frac{D}{2} = \frac{4}{2} = 2$ m
Instantaneous velocity $v = r w = r (2 π ν) = 2 \times 2 π \times 2 \approx 25$ $m / s$