Find out the loss in weight when 75 g of calcium carbonate is subjected to decomposition completely.
A
66 g
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B
22 g
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C
44 g
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D
33 g
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Solution
The correct option is D 33 g The chemical equation for the decomposition of CaCO3 can be written as: CaCO3→CaO+CO2 100 g of CaCO3 burns completely to produce 56 g of CaO. 75 g of CaCO3 burns completely to produce = 56100×75=42 g of CaO. Therefore, loss of weight of CaCO3=75−42=33 g