Find out the major product in given reaction.
$H_{5} C_{6} C H O + H_{3} C C H_{2} C H O d i l . N a O H - ----- \to ?$

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Solution

The reaction shown in the figure is an Aldol condensation reaction. It can be identified by presence of dil $N a O H$ as a catalyst for condensation of two aldehydes.
$H_{5} C_{6} C H O + C_{2} H_{5} C H O d i l N a O H - ------ \to C_{6} H_{5} C (O H) = C (C H_{3}) C H O$
* Final compound product is always $α - β$ unsaturated compound.

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