Find out the major product of the fission reaction of $^{235} U$ given below:
$_{92}^{235} U +_{0}^{1} p \to_{56}^{141} B a + 3_{0}^{1} p$ ?

Protons

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Neutrons

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Radiation

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Heat

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Light

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Solution

The correct option is D Heat
Nuclear fission reactions are accompanied with the emission of huge amounts of energy mostly in the form of heat.

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Similar questions

_{92}^{235} U +_{0}^{1} n \to_{40}^{94} Z r +_{52}^{139} T e + [?]_{0}^{1} n

^{235} U

_{92}^{235} U + N \to_{38}^{94} Sr +_{54}^{140} Xe + 2 n .

β

_{94}^{38} Sr

_{94}^{40} Zr

_{140}^{54} Xe

_{140}^{58} Ce .

m (^{235} U) = 235.439 u, m (n) = 1.00866 u, m (^{94} Z r) = 93.9064 u, m (^{140} C e) = 139.9055 u, 1 u = 931 M e V]

H_{5} C_{6} C H O + H_{3} C C H_{2} C H O d i l . N a O H - ----- \to ?

Major product of the reaction given below is

_{92}^{235} U +_{0}^{1} n \to ? +_{36}^{92} K r + 3_{0}^{1} n

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