Question

Find out the missing initial:
$\frac{2}{3}+\frac{?}{12}=\frac{1}{12}$

Answer 1

Given $\frac{2}{3}+\frac{?}{12}=\frac{1}{12}$

$⟹\frac{?}{12}=\frac{1}{12}-\frac{2}{3}$

$⟹\frac{?}{12}=\frac{1-4\times 2}{12}$

$⟹?=-7$