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Arithmetic Progression

Find out the ...

Question

Find out the missing number in the series: $2 + 7 + 9 + 3 + 8 + 11 + 4 + 9 + 13 +$ ___ $+ 10 + 15$ .

2

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3

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4

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5

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Solution

The correct option is D $5$
In the given sequence, there are three series,
First is AP with $a = 2$ and $d = 1$
Series will be : $2 + 3 + 4 + 5 + . . . . . . . . . .$
Second is AP with $a = 7$ and $d = 1$
Series will be : $7 + 8 + 9 + 10.......$
The third is AP with $a = 9$ and $d = 2$
Series will be : $9 + 11 + 13 + 15 + . . . . . . . . . . . . .$
So, the final series is
$2 + 7 + 9 + 3 + 8 + 11 + 4 + 9 + 13 + 5 + 10 + 15.$
So, th emissing term is $5$

Suggest Corrections

Similar questions

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

2, 2, 3, 4, 4,

, 6, 6, 7, 8, 8, 9....

64

Daily savings (in Rs.)	$1 - 3$	$3 - 5$	$5 - 7$	$7 - 9$	$9 - 11$	$11 - 13$	$13 - 15$
Number of children	$7$	$6$	$x$	$13$	$y$	$5$	$4$

8

x

y

\frac{11}{12} \div (\frac{5}{9} \times \frac{18}{25})

(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

\frac{15}{16}

(\frac{5}{6} - \frac{1}{2}) \div \frac{10}{11}

\frac{9}{8} \div \frac{3}{5}

(\frac{3}{4} + \frac{3}{5})

\frac{2}{5} \div {\frac{1}{5} o f [\frac{3}{4} - \frac{1}{2}] - 1}

(1 \frac{3}{4} \times 3 \frac{1}{7}) - (4 \frac{3}{8} \div 5 \frac{3}{5})

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