Question

Find out the missing particle in the following nuclear reaction?
${}_1^{2}H{+}_{29}^{63}Cu{\to }_{30}^{64}Zn+(?)$

• A. Proton
• B. Neutron
• C. Electron
• D. Positron
• E. Deuteron

Answer 1

Answer: (B)

Neutron

The given reaction : ${}_1^{2}H$ $+$ ${}_{29}^{63}Cu{\to }_{30}^{64}Zn$ $+$ ${}_Z^{A}X$

In a nuclear reaction, mass number and the atomic number are conserved.

$\therefore$ $2+63=64+A$ $⟹A=1$

Also, $1+29=30+Z$ $⟹Z=0$

Thus, the missing particle is ${}_0^{1}n$ i.e neutron.