Find out the molecular mass of the following compounds (Atomic Mass : Ca - 40 , N- 14 , C - 12 , O -16 , H- 1)

$a) Ca {({NO}_{3})}_{2} b) C_{12} H_{22} O_{11}$

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Solution

a) Molecular mass of $C a {(N O_{3})}_{2}$ = Atomic mass of Ca + 2 $\times$ Atomic mass of N + 6 $\times$ Atomic mass of O
= 40 + 2 $\times$ 14 + 6 $\times$ 16
= 164 u

b) Molecular mass of $C_{12} {H_{22} O}_{11}$ = 12 $\times$ Atomic mass of C + 22 $\times$ Atomic mass of H + 11 $\times$ Atomic mass of O
= 12 $\times$ 12 + 22 $\times$ 1 + 11 $\times$ 16
= 342 u

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Similar questions

(a) Define atomic mass unit.

(b) Calculate the molecular mass of the following :

(i) $C u S O_{4} .5 H_{2} O$ (ii) $(N H_{4})_{2} C O_{3}$

(iii) $(N H_{2})_{2} C O$ (iv) $M g_{3} N_{2}$

Given atomic mass of Cu = 63.5, H = 1, O = 16, C = 12, N = 14, Mg = 24, S = 32

C a (N O_{3})_{2}

C a = 40, N = 14, O = 16

(H_{2} S O_{4})

(K N O_{3})

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