Find out the percent composition by weight of $A l$ in ${{A l}_{2} ({S O}_{4})}_{3}$ ?

7.9%

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31.6%

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15.8%

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12.7%

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22.3%

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Solution

The correct option is C 15.8%
Molar mas of $A l_{2} (S O_{4})_{3}$ is 342.15 g/mol.
Molar mass of Al is 27 g/mol, hence, 2 moles of Al = 2 x 27 = 54 g.
Now, percentage composition of $A l$ = $100 \times 54 / 342.15 = 15.8$ %

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