Find out the point on the y axis which is equidistant from A(5,-2) and B(-3,2).
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Solution
Point on y-axis x=0 point=(0,y) equidistant from (5,-2) and(-3,2) distance from first point=(25+y^2+y-4y)^1/2 distance from second point=(9+y^2+4-4y)^1/2 both equals squaring both 29+y^2+4y=13+y^2-4y 8y=-16 y=-2 point=(0,-2)