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Question

Find out the quartile deviation for the given individual observations: 10,20,30,40,50, 60,70

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Solution

For the given data, N = 7

Q1=Size of(N+14)th item=Size of(7+14)th item= Size of 2nd item = 20Q1=20 and Q3=Size of 3(N+1)4th item=Size of 3(7+1)4th item = Size of 6th item = 60Q3=60Now,QD=Q3Q12=60202=402=20


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