Find out the quartile deviation for the given individual observations: 10,20,30,40,50, 60,70
For the given data, N = 7
Q1=Size of(N+14)th item=Size of(7+14)th item= Size of 2nd item = 20∴Q1=20 and Q3=Size of 3(N+1)4th item=Size of 3(7+1)4th item = Size of 6th item = 60∴Q3=60Now,QD=Q3−Q12=60−202=402=20