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Standard XII

Physics

Ohm's Law in Scalar Form

Find out the ...

Question

Find out the ratio of the current in $R_{1}$ to the current in $R_{2}$ .
Given the potential difference across $R_{1}$ is half the potential difference across $R_{2}$ and both resistance are of equal magnitude.

\frac{1}{4}

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\frac{1}{2}

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1

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Solution

The correct option is C $\frac{1}{2}$
By Ohm' law , current in $R_{1}$
$I_{1} = V / 2 R$
current in $R_{2}$
$I_{2} = V / R$
therefore , $I_{1} / I_{2} = 1 / 2$

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Find out the ratio of the current in R1 to the current in R2 .Given the potential difference across R1 is half the potential difference across R2 and both resistance are of equal magnitude.

The correct option is C 12By Ohm' law , current in R1 I1=V/2R current in R2 I2=V/Rtherefore , I1/I2=1/2

Find out the ratio of the current in $R_{1}$ to the current in $R_{2}$ .
Given the potential difference across $R_{1}$ is half the potential difference across $R_{2}$ and both resistance are of equal magnitude.

The correct option is C $\frac{1}{2}$
By Ohm' law , current in $R_{1}$
$I_{1} = V / 2 R$
current in $R_{2}$
$I_{2} = V / R$
therefore , $I_{1} / I_{2} = 1 / 2$