The correct option is B 160∘C
Let C be the temperature in Celsius scale and F be the temperature in Fahrenheit scale.
According to the question, if C=X then, F=2X
We know, C=59(F−32)
⇒X=59(2X−32)
⇒9X=10X−160
⇒10X−9X=160
⇒X=160∘C
Therefore, the temperature in degree Celsius scale at which the Fahrenheit scale will give twice the reading to that of Celsius scale is 160∘C