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Question

Find out the value of k for which the expression x2+(k+5)xk5=0 has two distinct real roots.

A
(, -9] U [-5, )
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B
(, -9) U (-5, )
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C
(, -9) U (-3, )
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D
(-9, -5)
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E
[-9, -5]
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Solution

The correct option is B (, -9) U (-5, )

Soln:

For the equation given D=(k+5)2+4(1)(k+5)=k2+10k+25+4k+20=k2+14k+45

For the equation to have two distinct roots: D>0

k2+14k+45>0 (k+9)(k+5)>0

Value of k will be (,9)(5,)

Hence option (b)


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