Find out whether or not the first polynomial is a factor of the second polynomial:
$4 a - 1, 12 a^{2} - 7 a - 2$

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Yes

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Can't determine

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None of the Above

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Solution

The correct option is A No
$3 a - 1$
$4 a - 1$ $12 a^{2} - 7 a - 2$
$12 a^{2} - 3 a$
$- 4 a - 2$
$- 4 a + 1$
$3$
Since we get the remainder $= 3$ ,
therefore, $4 a - 1$ it is not the factor of $12 a^{2} - 7 a - 2$ .

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Question 2 (ii)
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t^{2} - 3, 2 t^{4} + 3 t^{3} - 2 t^{2} - 9 t - 12

Question 2(i)
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$t^{2} - 3, 2 t^{4} + 3 t^{3} - 2 t^{2} - 9 t - 12$

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	$3 a - 1$
$4 a - 1$	$12 a^{2} - 7 a - 2$ $12 a^{2} - 3 a$
	$- 4 a - 2$ $- 4 a + 1$
	$3$

Find out whether or not the first polynomial is a factor of the second polynomial:4a−1,12a2−7a−2

The correct option is A No 3a−1 4a−112a2−7a−212a2−3a −4a−2−4a+1 3Since we get the remainder =3, therefore, 4a−1 it is not the factor of 12a2−7a−2.

Find out whether or not the first polynomial is a factor of the second polynomial:
$4 a - 1, 12 a^{2} - 7 a - 2$

The correct option is A No
$3 a - 1$
$4 a - 1$ $12 a^{2} - 7 a - 2$
$12 a^{2} - 3 a$
$- 4 a - 2$
$- 4 a + 1$
$3$
Since we get the remainder $= 3$ ,
therefore, $4 a - 1$ it is not the factor of $12 a^{2} - 7 a - 2$ .