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Question

Find out which of the following sequences are arithmetic progressions. For those which are arithmetic progressions, find out the common difference. 12,2,8,18,......

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Solution

Given sequence is,
12,2,8,18,...
first term of this A.P is a1=12
second term of this A.P is a2=2
third term of this A.P is a3=8
fourth term of this A.P is a4=18
the condition for an sequence to be an A.P is their must be a common difference (i.e.,d=an+1an)
putting n=1 in above equation
d=a2a1=212=10
putting n=2 in above equation
d=a3a2=82=10
putting n=3 in above equation
d=a4a3=18(8)=10
as we can see we get a common difference d=10 for this sequence
hence this sequence forms an A.P
with first term a1=12 and
common difference d=10

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