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Valency and Oxidation State

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Question

Find oxidation number of boron in $N a B H_{4}$ .

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Solution

$N a B H_{4} \to N a^{+} B H_{4}^{-} B H_{4}^{-} x - 4 \times 1 = - 1 x = - 1 + 4 x = 3 S o o x i d a t i o n n u m b e r o f B i n N a B H_{4} i s 3.$

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Valency and Oxidation State

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