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Question

Find p(0), p(1) and p(2) for each of the following polynomials:
1)p(y)=y2y+1
2)p(t)=2+t+2t2t3 [4 MARKS]

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Solution

Concept: 1 Mark
Application: 0.5 Mark each

1)p(y)=y2y+1.........(i)

Substituting the values in equation (i)
p(0)=020+1=1

p(1)=121+1=1

p(2)=222+1=3


2)p(t)=2+t+2t2t3........(1)

Substituting the values in equation (1)
p(0)=2+0+2(0)2(0)3=2

p(1)=2+1+2(1)2(1)3=4

p(2)=2+2+2(2)2(2)3=4


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