Find p(0), p(1) and p(2) for each of the following polynomials:
1)p(y)=y2−y+1
2)p(t)=2+t+2t2−t3 [4 MARKS]
Concept: 1 Mark
Application: 0.5 Mark each
1)p(y)=y2−y+1.........(i)
Substituting the values in equation (i)
p(0)=02−0+1=1
p(1)=12−1+1=1
p(2)=22−2+1=3
2)p(t)=2+t+2t2−t3........(1)
Substituting the values in equation (1)
p(0)=2+0+2(0)2−(0)3=2
p(1)=2+1+2(1)2−(1)3=4
p(2)=2+2+2(2)2−(2)3=4