Find p(0), p(1) and p(2) for each of the following polynomials:
$1) p (y) = y^{2} - y + 1$
$2) p (t) = 2 + t + 2 t^{2} - t^{3}$ [4 MARKS]

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Solution

Concept: 1 Mark
Application: 0.5 Mark each

$1) p (y) = y^{2} - y + 1$ .........(i)

Substituting the values in equation (i)
$p (0) = 0^{2} - 0 + 1 = 1$

$p (1) = 1^{2} - 1 + 1 = 1$

$p (2) = 2^{2} - 2 + 1 = 3$

$2) p (t) = 2 + t + 2 t^{2} - t^{3}$ ........(1)

Substituting the values in equation (1)
$p (0) = 2 + 0 + 2 {(0)}^{2} - {(0)}^{3} = 2$

$p (1) = 2 + 1 + 2 {(1)}^{2} - {(1)}^{3} = 4$

$p (2) = 2 + 2 + 2 {(2)}^{2} - {(2)}^{3} = 4$

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Similar questions

Find p(0), p(1) and p(2) for each of the following polynomials:
$1) p (y) = y^{2} - y + 1$
$2) p (t) = 2 + t + 2 t^{2} - t^{3}$ [4 MARKS]

p (y) = y^{2} - y + 1

p (t) = 2 + t + 2 t^{2} - t^{3}

p (0), p (1)

p (2)

p (y) = y^{2} - y + 1

p (t) = 2 + t + 2 t^{2} - t^{3}

p (x) = x^{3}

p (x) = (x - 1) (x + 1)

p (0), p (1), p (2)

p (t) = 2 + t + 2 t^{2} + t^{3}

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