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Question

Find p(0), p(1) and p(2) for each of the following polynomials:
(i) p(y)=y2y+1
(ii) p(t)=2+t+2t2t3

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Solution

(i)
p(y)=y2y+1p(0)=020+1=1p(1)=121+1=1
p(2)=222+1=3.

(ii)
p(t)=2+t+2t2t3p(0)=2+0+2×0203=2p(1)=2+1+2×1213=4
p(2)=2+2+2×2223=4+88=4.

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