Question

Find $p\left(0\right),p\left(1\right)$ and $p\left(2\right)$ for polynomial $p\left(x\right)=x^2-x+1$.

• A. $1,2,1$
• B. $1,1,3$
• C. $1,-1,2$
• D. $1,1,-2$

Answer 1

Answer: (B)

$1,1,3$

Given polynomial is $p\left(x\right)=x^2-x+1$

Replace $x$ by $0$, we get

$p\left(0\right)=(0{)}^2-0+1$

$\Rightarrow p\left(0\right)=0+0+1=1$

Replace $x$ by $1$, we get

$p\left(1\right)=(1{)}^2-1+1$

$\Rightarrow p\left(1\right)=1-1+1=1$

Replace $x$ by $2$, we get

$p\left(2\right)=(2{)}^2-2+1$

$\Rightarrow p\left(2\right)=4-2+1=3$