Find $p (0), p (1)$ and $p (2)$ for polynomial $p (y) = 2 + y + 2 y^{2} - y^{3}$ .

2, 4, 4

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2, 3, 4

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1, 1, 2

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2, 3, 1

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Solution

The correct option is C $2, 4, 4$
Given polynomial is $p (y) = 2 + y + 2 y^{2} - y^{3}$
Replace $y$ by $0$ , we get
$p (0) = 2 + (0) + 2 (0)^{2} - (0)^{3}$
$\Rightarrow p (0) = 2 + 0 + 0 + 0$
$\Rightarrow p (0) = 2$
Replace $y$ by $1$ , we get
$p (1) = 2 + 1 + 2 (1)^{2} - (1)^{3}$
$\Rightarrow p (1) = 2 + 1 + 2 - 1$
$\Rightarrow p (1) = 4$
Replace $y$ by $2$ , we get
$p (2) = 2 + 2 + 2 (2)^{2} - (2)^{3}$
$\Rightarrow p (2) = 2 + 2 + 8 - 8$
$\Rightarrow p (2) = 4$

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