Question

Find $p\left(0\right),p\left(1\right),p\left(2\right)$ for $p\left(x\right)=x^3$

• A. $p\left(0\right)=0$
• B. $p\left(1\right)=1$
• C. $p\left(2\right)=8$
• D. All of the above

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A All of the above
B $p\left(1\right)=1$
C $p\left(2\right)=8$
D $p\left(0\right)=0$

Here, $p\left(x\right)=x^3$
Now, $p\left(0\right)=0^3=0$
$p\left(1\right)=1^3=1$
$p\left(2\right)=2^3=8$