Question

Find P, Q, R and S.
(i) The sum of two integers is $71$. If one of them is $-101$, then other integer is $\underset{–}{P}$.
(ii) The product of an integer and $\underset{–}{Q}$ is zero.
(iii) $\underset{–}{R}$ is the quotient when an integer is divided by itself.
(iv) Additive inverse of $-7$ is $\underset{–}{S}$.

• A. P-$172$, Q-$0$, R-$1$, S-$7$
• B. P-$184$, Q-$1$, R-$2$, S-$7$
• C. P-$172$, Q-$1$, R-$1$, S-$7$
• D. P-$172$, Q-$0$, R-$2$, $7$

Answer 1

Answer: (A)

P-$172$, Q-$0$, R-$1$, S-$7$

(i) Let the other integer be P
One integer $=-101$
$\therefore$ According to question, $P-101=71$
$\Rightarrow P=71+101=172$
$\therefore$ Other integer $=P=172$
(ii) Let the integer be x
According to question, $x\times Q=0\Rightarrow Q=\frac{0}{x}=0$
(iii) Let integer be x
According to question, $x÷x=R\Rightarrow R=1$
(iv) $S=7$.