Find the particular solution of the differential equation x2dy=(2xy+y2)dx, given that y= 1 when x = 1.
OR
Find the particular solution of the differential equation (1+x2)dydx=(emtan−1x−y), given that y =1 when x = 0.
Show that the general solution of the differential equation is given by (x + y + 1) = A (1 – x – y – 2xy), where A is parameter