CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector of the Segment

Find perimete...

Question

Find perimeter and area formed by the length and breadth of the given rectangle.

Open in App

Solution

$P e r i m e t e r = 2 (\frac{9}{2} + \frac{7}{2}) c m$
$= 16 c m$
$A r e a = \frac{9}{2} \times \frac{7}{2}$
$= \frac{63}{4} s q c m$ or $15 \frac{3}{4} s q c m$ .

Suggest Corrections

thumbs-up

1

Similar questions

Q. Length of rectangle is

8

cm and area of rectangle

56 {cm}^{2}

. Find the perimeter of rectangle and its breadth.

Q. The length of a rectangle is twice its breadth. The perimeter of the rectangle is

120 c m

. Find the length and breadth of this rectangle. Also find its area,

Q. The perimeter of a rectangle is

104 m

640 m^{2}

. Find its length and breadth.

Q. The length of a rectangle exceeds the breadth by

3 m

and the perimeter is

5

times the breadth. Find the length, breadth and perimeter of the rectangle.

Find the length and perimeter of a rectangle, whose: area $= 120 c m^{2}$ and breadth =8 cm

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector of the Segment

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon