Question

Find potential difference between the point $\text{A}$ and $\text{B}$ (in volts)

• A. $3\text{V}$
• B. $5\text{V}$
• C. $6\text{V}$
• D. $9\text{V}$

Answer 1

The correct option is C $6\text{V}$


By using KVL to the given loop,

$12-\frac{q}{C_1}-2-\frac{q}{C_2}=0$

$10=q[\frac{1}{C_1}+\frac{1}{C_2}]=q[\frac{1}{3}+\frac{1}{2}]$

$10=\frac{5q}{6}$

$q=12\mu \text{C}$


Potential difference between $A$ and $B$ is,

$V_A-\frac{q}{C_2}=V_B$

$V_A-V_B=\frac{q}{C_2}=\frac{12\times {10}^{-6}}{2\times {10}^{-6}}$

$\therefore V_A-V_B=6\text{V}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (c) is the correct answer.