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Question

Find principal solution for tanx=1. xϵ(π2,π)

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Solution

tanx=1
Here, tan is negative.
We know, tan is negative in 2nd and 4th quadrant.
Here, θ=45o
Value in 2nd quadrant = 180o45o=135o
Value in 4th quadrant = 360o45o=315o
So, principal solutions are
x=135o=3π4 and x=315o=7π4.

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