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Question

Find product of following pairs of monomials
(i) 4,7p
(ii) 4p,7p
(iii) 4p,7pq
(iv) 4p3,3p
(v) 4p,0

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Solution

(i) 4×7×p=28p

(ii) 4p×7p=28p2

(iii) 4p×7pq=28p2q

(iv) 4p3×3p=12p4

(v) 4p×0=0

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