Find proportionaly constant for thr data given, is:
$x$ $2$ $4$ $5$
$y$ $18$ $9$ $6$

\frac{1}{9}

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1

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\frac{2}{3}

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None of the above

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Solution

The correct option is D None of the above
Let $x = \frac{k}{y} \Rightarrow k = x y$
For $x = 2, y = 11 k = \frac{2}{11} = \frac{1}{9}$

For $x = 4, y = 9 k = \frac{4}{9}$

For $x = 5, y = 6 k = \frac{5}{6}$
$∵ k$ is not a constant in all three cases

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Similar questions

Q. Find inverse proportionaly constant if

x

and

y

are in inverse proportion.

$x$	$9$	$6$	$3$	$18$
$y$	$2$	$3$	$6$	$1$

Find the mode of the following data set.

1, 2, 6, 9, 5, 9, 4, 18, 14, 2, 8, 11, 7

Q. The distance between lines

\frac{x + 5}{4} = \frac{y + 3}{- 18} = \frac{z - 6}{- 4}

and

\frac{x - 3}{2} = \frac{y + 10}{- 9} = \frac{z - 1}{- 2}

(approx.) is

$x$	$f (x)$
$1$	$1$
$2$	$3$
$3$	$5$
$4$	$7$
$5$	$9$
$6$	$11$

For the function in the table above,
If

f (2) = b

, then find

f (2 b)

Expand:
(1) $(a + 2) (a - 1)$
(2) $(m - 4) (m + 6)$
(3) $(p + 8) (p - 3)$
(4) $(13 + x) (13 - x)$
(5) $(3 x + 4 y) (3 x + 5 y)$
(6) $(9 x - 5 t) (9 x + 3 t)$
(7) $(m + \frac{2}{3}) (m - \frac{7}{3})$
(8) $(x + \frac{1}{x}) (x - \frac{1}{x})$
(9) $(\frac{1}{y} + 4) (\frac{1}{y} - 9)$

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Find proportionaly constant for thr data given, is:x245y1896

The correct option is D None of the aboveLet x=ky⇒k=xyFor x=2,y=11k=211=19For x=4,y=9k=49For x=5,y=6k=56∵k is not a constant in all three cases

Find proportionaly constant for thr data given, is:
$x$ $2$ $4$ $5$
$y$ $18$ $9$ $6$

The correct option is D None of the above
Let $x = \frac{k}{y} \Rightarrow k = x y$
For $x = 2, y = 11 k = \frac{2}{11} = \frac{1}{9}$

For $x = 4, y = 9 k = \frac{4}{9}$

For $x = 5, y = 6 k = \frac{5}{6}$
$∵ k$ is not a constant in all three cases