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Question
Find pythagorean triplet with the smallest number as 10
Find pythagorean triplet with the smallest number as 10
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Solution
The formula is (2m)²,(m² - 1)²,(m² + 1)²
Smallest member = 2m = 10
2m = 10
m = 10/2 = 5
m² - 1 = 5² - 1 = 25 - 1 = 24
m² + 1 = 5² + 1 = 25 + 1 = 26
The required triplet is 10 , 24 and 26.
Smallest member = 2m = 10
2m = 10
m = 10/2 = 5
m² - 1 = 5² - 1 = 25 - 1 = 24
m² + 1 = 5² + 1 = 25 + 1 = 26
The required triplet is 10 , 24 and 26.
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