Find Q in the addition.
3 1 Q+1 Q 3 –––––––– 5 0 1 ––––––––
8
Since ones digit of (Q + 3) = 1,
trying all the digits from 0 to 9 we can see that on adding 8 to 3, the ones digit of the sum is 1.
⇒ Q + 3 = 8 + 3 = 11
(1 in ones place of the sum and the other 1 is carried over to the tens place column)
So, the value of Q is 8 and by further proceeding the addition we can verify this.
Now, considering tens place column,
1(carry) + 1 + 8 = 10 (0 in tens place of the sum and 1 carried over to the thousands place column)
Now, considering thousands place column, 1(carry) + 3 + 1 = 5
3 1 8+1 8 3 –––––––– 5 0 1 ––––––––