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Question
Findthetrignometricfunctionsof(1)5π6(2)225∘(3)−2π3(4)11πC3(5)−630∘
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Solution
(1) sin5π6=12csc5π6=2cos5π6=−√32sec5π6=−2√3tan5π6=−1√3cot5π6=−√3
(2) sin225∘=−1√2csc225∘=−√2cos225∘=−1√2sec225∘=−√2
tan225∘=1cot225∘=1
(3) sin(−2π3)=−√32csc(−2π3)=−2√3
cos(−2π3)=−12sec(−2π3)=−2tan(−2π3)=√3cot(−2π3)=1√3
(4) sin(11π3)=−√32csc(11π3)=−2√3cos(11π3)=12sec(11π3)=2tan(11π3)=−√3cot11π3=−1√3
(5) sin(−630∘)=1csc(−630∘)=1cos(−630∘)=0sec(−630∘)=−∞
tan(−630∘)=∞cot(−630∘)=0
(1) sin5π6=12csc5π6=2
cos5π6=−√32sec5π6=−2√3
tan5π6=−1√3cot5π6=−√3
(2) sin225∘=−1√2csc225∘=−√2
cos225∘=−1√2sec225∘=−√2
tan225∘=1cot225∘=1
(3) sin(−2π3)=−√32csc(−2π3)=−2√3
cos(−2π3)=−12sec(−2π3)=−2
tan(−2π3)=√3cot(−2π3)=1√3
(4) sin(11π3)=−√32csc(11π3)=−2√3
cos(11π3)=12sec(11π3)=2
tan(11π3)=−√3cot11π3=−1√3
(5) sin(−630∘)=1csc(−630∘)=1
cos(−630∘)=0sec(−630∘)=−∞
tan(−630∘)=∞cot(−630∘)=0Suggest Corrections
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