R_eq=? 1R'=1R+1R+1R =3R R'=R3 Since R' is attached in series to R #160; R'R=R3+R =4R3 ...

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Standard XII

Mathematics

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Find Req

Question

Find $R_{e q}$

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Solution

$R_{e q} = ?$

$\frac{1}{R^{'}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R}$

$= \frac{3}{R}$

$R^{'} = \frac{R}{3}$

Since $R^{'}$ is attached in series to $R$

$R^{'} R = \frac{R}{3} + R$

$= \frac{4 R}{3}$

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Find Req

Req=?1R′=1R+1R+1R=3RR′=R3Since R′ is attached in series to R R′R=R3+R=4R3

Find $R_{e q}$

$R_{e q} = ?$

$\frac{1}{R^{'}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R}$

$= \frac{3}{R}$

$R^{'} = \frac{R}{3}$

Since $R^{'}$ is attached in series to $R$

$R^{'} R = \frac{R}{3} + R$

$= \frac{4 R}{3}$