Consider the given equation.
5Pr=6Pr−1
5!(5−r)!r!=6!(6−r+1)!(r−1)!
5!(5−r)!r(r−1)!=6!(5−r)!(r−1)!
5!r=6!1
r=5!6!=16
Hence, this is the answer.
Find r if (i) (ii) .