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Byju's Answer
Standard XII
Physics
Problem Solving
find range of...
Question
find range of projectile when equation of trajectory is given by y=ax-bx^2
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Similar questions
Q.
Trajectory of a projectile is
y
=
A
x
−
B
x
2
. It's horizontal range is:
Q.
The equation of a projectile is
y
=
a
x
−
b
x
2
. Its horizontal range is
Q.
The equation of trajectory of projectile is given by
y
=
x
√
3
−
g
x
2
20
, where
x
and
y
are in meter. The maximum range of the projectile is
Q.
The equation of a projectile is
y
=
a
x
−
b
x
2
. Its horizontal range is
Q.
The equation of trajectory of a projectile is
y
=
10
x
,
(
5
9
)
x
2
. If we assume
g
=
10
m
s
−
2
the range of projectile ( in metres) is:
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