Find remainder $\frac{51^{49}}{1}$

Open in App

Solution

When we divide any number by $1$ we get the remainder is zero.

So, the remainder when $51^{49}$ is divided by $1$ is zero

Suggest Corrections

Similar questions

51^{49} + 51^{48} + 51^{47} + . . . + 51 + 1

Using Remainder theorem, find the remainder when 3x⁴ – 4x³ – 3x – 1 by x - 1.

x^{3} - 3 x^{2} + x + 1

x - 1

x^{3} + x^{2} + x + 1

x - \frac{1}{2}

(3 x^{2} - 7 x + 5) is divided by (x - 1) .

Join BYJU'S Learning Program