Find roots of equation $a^{4} x^{2} - b^{4} = 0$

b^{2} / a^{2}, - b^{2} / a^{2}

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b^{2} / a^{2}, b^{2} / a^{2}

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a^{2} / b^{2}, \frac{a^{2}}{b^{2}}

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a^{2} / b^{2}, - \frac{a^{2}}{b^{2}}

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Solution

The correct option is A $b^{2} / a^{2}, - b^{2} / a^{2}$
$a^{4} x^{2} - b^{4} = 0$
Since, $(a^{2} - b^{2}) = (a - b) (a + b)$
$(a^{2} x + b^{2}) (a^{2} x - b^{2}) = 0, a^{2} x = b^{2} a n d, a^{2} x = - b^{2}$
$x = b^{2} / a^{2}, x = - b^{2} / a^{2}$

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x^{2} - y^{2} = 0

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