Find S1+S2+S3.....S10 given that Sn= 1+2+3+4.....n
220
S1= 1
S2= 1+2 =3
S3=1+2+3= 6
This is of the form n(n+1)2
We need to find ∑n(n+1)2 where n=10
Expanding we get
12[∑n2+∑n]
12[n(n+1)(2n+1)6+n(n+1)2]
Substitute n=10 to get the answer as 4402=220