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Question

Find S1+S2+S3.....S10 given that Sn= 1+2+3+4.....n

A

260

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B

240

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C

340

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D

220

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Solution

The correct option is D

220


S1= 1

S2= 1+2 =3

S3=1+2+3= 6

This is of the form n(n+1)2

We need to find n(n+1)2 where n=10

Expanding we get

12[n2+n]

12[n(n+1)(2n+1)6+n(n+1)2]

Substitute n=10 to get the answer as 4402=220


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