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Question

Find sin x2, cos x2 and tan x2 in the following:

cos x = 13, x in quadrant III.

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Solution

Here cos x = 13, x in quadrant III.

Now π<x<3π2π2<x2<3π4

So x2 lies in second quadrant.

sin x2 is positive and cos x2, tan x2 are negative.

Now cos x2=1+ cos x2=1132

=- 13×53=33

sin x2=1- cos x2=1+132

= 23×33=63

tan x2=sinx2cosx2=2313=2.


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