Question

Find solution of the given equation

$\frac{x+5}{1}=\frac{2x+10}{x-6}$

• A. $x=7,x=-6$
• B. $x=5,x=-8$
• C. $x=-3,x=-5$
• D. $x=8,x=-5$

Answer 1

The correct option is D

$x=8,x=-5$

$\frac{x+5}{1}=\frac{2x+10}{x-6}$

After cross multiplication,

$(x+5)\times (x-6)=(2x+10)\times \left(1\right)$

$x^2-x-30=2x+10$

$\Rightarrow x^2-3x-40=0$ is in the form of $a{x}^2+bx+c$ = 0 [Quadratic equation]

By using factorization method

$\to$ $x^2-3x-40=0$

$x^2-(8-5)x-40$

$x^2-8x+5x-40$

$x(x-8)+5(x-8)$

$(x-8)(x+5)$

$\to$ $x=8,orx=-5$