Find solution of the given equation
x+51=2x+10x−6
True
x+51=2x+10x−6
After cross multiplication,
(x+5)×(x−6)=(2x+10)×(1)
x2−x−30=2x+10
⇒x2−3x−40=0 is in the form of ax2+bx+c = 0 [Quadratic equation]
By using factorization method
→ x2−3x−40=0
x2−(8−5)x−40
x2−8x+5x−40
x(x−8)+5(x−8)
(x−8)(x+5)
→ x=8,orx=−5