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B
±(3−4i).
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C
±(4−3i).
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D
±(4+3i).
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Solution
The correct option is B±(3−4i). Let square root of −7−24i is z ⇒z2=−7−24i=−7−2⋅3⋅4i ⇒z2=−16+9−2⋅3⋅4i ⇒z2=16i2+9−2⋅3⋅4i=(−4i)2−2⋅3⋅4i+(3)2 ⇒z2=(3−4i)2,[∵(a−b)2=a2−2ab+b2] ∴z=±(3−4i)