Find square root of -8+6i

\pm (1 + 3 i) .

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\pm (1 - 3 i) .

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\pm (3 + i) .

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\pm (3 - i) .

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Solution

The correct option is A $\pm (1 + 3 i) .$
$- 8 - 6 i .$
Half the coefficient of i is 3 whose factors are 3 and 1 and since the real part is -8, we take the factors as 1 and 3 such that $1^{2} - 3^{2} = - 8$
$∴ \sqrt{(- 8 + 6 i)} = \pm (1 + 3 i) .$
Ans: A

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