Find -k-0-1223k - -k-018-12k -

∑^∞_k=012(23)^k=12[(23)^o+(23)+(23)^2+....∞] =12(1 23)=36 ( ∵ it is a sum of ∞ G.P with r lt; 1 ) ∑ 18( 12)^k=18[1+( 12)+( 12)^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Binomial Coefficients

Find ∑k=0∞1...

Question

Find $\sum_{k=0}^{\infty}12(\dfrac{2}{3})^k - \sum_{\infty}^{k=0}18(\dfrac{-1}{2})^k =$

Open in App

Solution

Suggest Corrections

Similar questions

$X = x$	$0$	1	2	3	4	5	6	7
$P (X = x)$	$0$	$k$	$2 k$	$2 k$	$3 k$	$K^{2}$	$2 k^{2}$	$7 k^{2} + k$

P (0 < X < 5) =

l i m n \to θ (\frac{1^{k} + 2^{k} + 3^{k} + . . . . . k}{n^{k + 1}}) = (k > - 1)

X

$X = x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P (X = x)$	$0$	$k$	$2 k$	$2 k$	$3 k$	$k^{2}$	$2 k^{2}$	$7 k^{2} + k$

k

P (0 < X < 5)

X

$X$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P (X = x)$	$0$	$k$	$2 k$	$2 k$	$3 k$	$k^{2}$	$2 k^{2}$	$7 k^{2} + k$

k

k,

A (k + 1, 2 k), B (3 k, 2 k + 3)

C (5 k + 1, 5 k)

Join BYJU'S Learning Program