Find $20 \sum r = 0$ $^{20} C_{r} 3^{r}$

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Solution

$\sum_{r = 0}^{20}^{20} C_{r} \times 3^{r} \times 1^{20 - r} = (1 + 3)^{20} = 4^{20}$

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Find 20∑r=020Cr3r

∑20r=020Cr×3r×120−r=(1+3)20=420

Find $20 \sum r = 0$ $^{20} C_{r} 3^{r}$

$\sum_{r = 0}^{20}^{20} C_{r} \times 3^{r} \times 1^{20 - r} = (1 + 3)^{20} = 4^{20}$