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Byju's Answer
Standard XII
Mathematics
A.G.P
Find sum of s...
Question
Find sum of series
n
+
(
n
−
1
)
x
+
(
n
−
2
)
x
2
+
.
.
.
.
+
2
x
n
−
2
+
x
n
−
1
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Solution
consider,
S
=
n
+
(
n
−
1
)
x
+
(
n
−
2
)
x
2
+
.
.
.
.
.
.
+
x
n
−
1
x
S
=
n
x
+
(
n
−
1
)
x
2
+
.
.
.
.
.
+
2
x
n
−
1
+
x
n
⇒
x
S
−
S
=
n
+
(
n
−
(
n
−
1
)
)
x
+
(
(
n
−
1
)
−
(
n
−
1
)
)
x
+
(
n
−
2
)
−
(
n
−
3
)
x
3
x
n
−
1
+
x
n
⇒
(
x
−
1
)
S
=
n
+
(
x
+
x
2
+
.
.
.
.
.
.
x
n
−
1
+
x
n
)
⇒
(
x
−
17
S
)
=
n
+
x
(
x
n
−
1
x
−
1
)
⇒
X
=
n
x
−
1
+
x
(
x
n
−
1
)
(
x
−
1
)
2
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0
Similar questions
Q.
Find the sum to
n
terms of the series
n
+
(
n
−
1
)
x
+
(
n
−
2
)
x
2
+
.
.
.
+
2
x
n
−
2
+
x
n
−
1
Q.
Let
x
1
=
1
,
x
3
=
4
and
x
n
+
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=
2
x
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+
2
+
2
x
n
+
2
−
x
n
for all
n
≥
1.
Prove that
x
n
is a square for all
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1.
Q.
Find the sum of the series
1.
n
+
2.
(
n
−
1
)
+
3.
(
n
−
2
)
+
4.
(
n
−
3
)
+
.
.
.
.
+
(
n
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)
.2
+
n
.1
.
Also, find the coefficient of
x
n
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1
in the expansion of
(
1
+
2
x
+
3
x
2
+
.
.
.
.
+
n
x
n
−
1
)
2
Q.
C
0
+
C
1
x
2
+
C
2
X
2
3
+
…
C
n
X
n
n
+
1
=
Q.
Find the sum of the series : 1.n+2. (n-1) + 3.(n-2)+....+(n-1).2+n.1.
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