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Byju's Answer
Standard XII
Mathematics
Integration by Substitution
Find sum of t...
Question
Find sum of the following surds:
(
√
x
+
2
√
y
)
,
(
2
√
x
−
3
√
y
)
,
(
3
√
x
+
√
y
)
.
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Solution
The sum of the given surds can be determined as follows:
(
√
x
+
2
√
y
)
+
(
2
√
x
−
3
√
y
)
+
(
3
√
x
+
√
y
)
=
(
√
x
+
2
√
x
+
3
√
x
)
+
(
2
√
y
+
√
y
−
3
√
y
)
=
√
x
(
1
+
2
+
3
)
+
√
y
(
2
+
1
−
3
)
=
6
√
x
+
0
√
y
=
6
√
x
Hence,
(
√
x
+
2
√
y
)
+
(
2
√
x
−
3
√
y
)
+
(
3
√
x
+
√
y
)
=
6
√
x
.
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x
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3
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