Question

Find sum of the real solution of given equation
${(x+\frac{1}{x})}^2=3(x+\frac{1}{x})+4$

Answer 1

${(x+\frac{1}{x})}^2=3(x+\frac{1}{x})+4$

$\Rightarrow$ Let $(x+\frac{1}{x})=y$

then $y^2-3y-4=0$

So, it's quadratic equation.